Graphical Concepts 1
y-int
?
x-int
?
y=0
?
x=0
?
x-int @ x=
y-int @ y=
(m,0)
(0,n)
f(0)=
f(j)=
(0,k)
(j,0)
x-int:
e+f =
y-int:
y = a
2
c
e
(m,n)
f
LoS:
(-e) x (-f) =
f(m) =
concave
e
(m,n)
c
f
T.P.=
concave
y = a
2
c
x
y
0
p
?
?
?
?
?
?
0
x
y
c
k
(p,q)
k
a
0
p+a
?
?
q
k
e
x
y
e
n
c
(p,q)
0
q
m
m
0
f
x
y
0
1
?
?
1
y=bx
1
x
y
0
1
?
?
y=a(bx)
1
-1
1
y=bx
-1
m x n =
y=a/x
n
m
n
g(a)=
f(0)=
f(a)=
g(x)
=g(0)
f(x)=origin=g(x)
?
f(x)
k
f(x)=g(x)
?
a
g(x)
f(x)
g(x)=f ⇨ x=
f(x)=b ⇨ x=
(a,b)
d
c
f(0)=
(e,f)
f(x)=g(x) for
x=
g(0)=
x=
g(x)
f(x)
x
a
e
0
e
j
b
f(a)
k
c
g(b)
d
j
j
f(x)
g(x)
Students who took this test also took :

Created with That Quiz — where test making and test taking are made easy for math and other subject areas.