Substitution/Elimination

Solving Systems of Equation Using ELIMINATION Solving Systems of Equations Using SUBSTITUTION First, make sure that one set of variables has opposite coefficients. Fill in all the blanks, then press "ok" { (-4) + 5y = 1 -2x - 5y = 11 -x + 5y = 1 y = answer + -2x - 5y = 11 -x + 5y = 1 ( , ) x = = 12 Solve { -2x + 2y = 8 4x - 2y = 6 Answer ( , ) Sometimes, you will have to multiply one of the equations by a number to get one set of "opposite variables." { What should you multiply the second equationby to make the x variable "opposite variables?" 3x - 4y = -1 x - 6y = -5 -6 3 -3 -4 Solve this system. { 3x - 4y = -1 x - 6y = -5 ( , ) { Solve. 3x - y = 11 5x + 3y = 9 ( , ) Solve. ( , ) Solve. ( , ) + Solve for y. -6x + 21y = -24 6x - 4y = 24 the x-coordinate is the y-coordinate is Then solve for x. Is (5, -2) a solution of { 3x + 4y = 7 x - 2y = 9 Yes No ? Is (-1, 4) a solution of this system? Yes No Solve. ( , ) |

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