Factorizing different of two squares
x2 – 4 =
factorize completely
(x + 4)(x - 1)
(x – 2)(x - 2)
(x – 4)(x – 1)
(x + 2)(x – 2)
9x2 - 1 =
factorize completely
(3x + 1)(3x - 1)
(3x + 1)(3x + 1)
(3x – 1)(3x – 0)
(9x + 1)(x – 1)
4x2 – 25=
factorize completely
(2x + 5)(2x + 5)
(2x – 25)(2x - 1)
(2x + 5)(2x – 5)
(2x - 5)(2x – 5)
x2  – 1 =
factorize completely
(2x + 1)(x - 1)
(x + 1)(x + 1)
(x – 1)(x – 1)
(x + 1)(x – 1)
4x2  – 9y2 =
factorize completely
(4x + 3y)(x - 3y)
(2x + 3)(x - 3)
(2x – 3y)(2x – 3y)
(2x + 3y) (2x – 3y)
25x2  – 36 =
factorize completely
(5x – 3)(5x + 12)
(5x + 6)(5x - 6)
 (5x - 63)(5x – 6)
(5x + 6)(5x + 6)
47x2 - 25 =
factorize completely
(7x +5 )(7x - 5)
(7x -5 )(7x - 5)
(7x -5 )(7x - 5)
(3x +5 )(x - 2)
4𝑥2  − 9 =
factorize completely
(2x – 3)(x + 4)
(2x – 3)(2x + 3)
 (2x - 3)(x + 3)
(2x - 4)(2x – 3)
2𝑥2 − 50  =
take H.C.F first
factorize completely
2 ( 𝑥2 − 25 )
(x – 5)(x - 5)
(x + 5)(x - 5)
(x + 5)x + 5)
2(x – 5)(x + 5)
2y2 - 18 = 2 ( y2  -  9 )
take H.C.F first
factorize completely
2(y - 3)(y - 3)
2(y + 3)(y - 3)
(y - 3)(y + 4)
(y + 3)(y + 3)
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