MAT Review for Calc Unit 1
 Use the graph of f(x) below to find the following limit.-101dnelimx→1+f(x) = Use the graph of f(x) below to find the following limit.-101dnelimx→1-f(x) = Use the graph of f(x) below to find the following limit.-101dnelimx→1f(x) = Use the graph of f(x) below to find the following limit.0+∞-∞dnelimx→4+f(x) = Use the graph of f(x) below to find the following limit.0+∞-∞dnelimx→3f(x) = Identify the type of discontinuity and where itoccurs for the following function.jump at x = 3point at x = 3infinite at x = 3continuousf(x) =  4x - 3 Identify the type of discontinuity and where itoccurs for the following function.jump at x = -2point at x = -2infinite at x = -2continuousf(x) = 3x + 6 Identify the type of discontinuity and where itoccurs for the following function.infinite at x = 3, point at x = 2infinite at x = 2, point at x = 3infinite at x = 3, infinite at x = 2point at x = 2, point at x = 3f(x) =      x - 2x2 - 5x + 6 Identify the type of discontinuity and where itoccurs for the following function.cont. when x ≤ -5/3cont. when x ≥ -5/3cont. when x = -5/3continuousf(x) = √3x + 5 Identify the type of discontinuity and where itoccurs for the following function.cont. when x ≤ 7/4cont. when x ≥ 7/4cont. when x = 7/4continuousf(x) = √4x - 73 Find the average rate of change over the given interval.f(x) = 4x - 5      [2, 4]1/43412 Find the average rate of change over the given interval.f(x) = 3x2 - 2x +1      [-2, 3]-5-115 Find the limit h→0 of the average rate of change of f(x) = x2 - 2x - 5 at x = 4.681019 Find the slope of the line tangent to the curve              f(x) = x3 - 4x + 2 at x = 2.36 810 Find the limit of the following problem.-7+∞-∞does not existlimx→-3x + 3x - 4 Find the limit of the following problem.x→-2+lim-5 5+∞does not exist(x + 7)x + 2x + 2 Find the limit of the following problem.x→3-lim-22 -889{2x + 3 if x ≥ 35x - 7 if x ≤ 3 Find the equation of the line tangent to the curve.y - 3 = 12(x - 7)y - 3 = 4(x - 7)y - 7 = 12(x - 3)y - 7 = 4(x - 3)f(x) = 4x + 9 at (3, 7) Find the equation of the line normal to the curve.y - 4 = 7(x - 2)y - 4 = -7(x - 2)y - 4 = 1/7(x - 2)y - 4 = -1/7(x - 2)f(x) = 3x2 - 5x at (2, 4) Find the equation of the line tangent to the curve.y + 1 = 11(x - 2)y + 1 = -13(x - 2)y - 1 = 11(x + 2)y - 1 = -13(x + 2)f(x) = x3 - x + 5 at (-2, 1)
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