Trigonometry Quiz
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cos(x) tan(x) cot(x) csc(x) The graph of y = sec(x) has the same set of asymptotes as the graph of y = If t≠0 what is the range of the function y=tsec(x) [-t,t] (-∞,∞) y≤-t or y≥t y≤-1/t or y≥1/t  Determine the quadrant of the terminal side of the angle in standard position. Convert degree measures to radians. measure in radians: Quadrant: (write number 1,2,3 or 4) π  sin(θ) = cos(θ) = cot(θ) = csc(θ) = sec(θ) = State the amplitude, period, phase shift,and range for the functiony=-4cos(2x-1) amplitude: period: phase shift: π ≤y≤ Range: Find the exact value of x without using a calculator. csc(x) =-1 0≤x≤2π Give your answer in radians: π  Evaluate: π  Evaluate: π  Range: State the domain and range: Domain: π ≤ ≤y≤ x ≤ π Point P(-3,6) is on the terminal side of angle θ. Evaluate the six trigonometric functions for θ.Denote square root by writing sqrt, e.g. √2 = sqrt2 sin(θ) = cos(θ) = cot(θ) = tan(θ) = sec(θ) = csc(θ)= is odd so tan(-x)=tan(x) is even so tan(-x)=tan(x) is odd so tan(-x)=-tan(x) is even so tan(-x)=-tan(x) Tangent function  a) b) sinθ= (smaller value) θ= degrees or sinθ= θ= (bigger value) degrees   Write down the period of the function: degrees The value of :f(90o) = Solve f(x)=0for -360o≤x≤360o degrees (smaller value) (greater value) degrees  Find the shaded area: Round your answer to 1 decimal place mm2 Find the area of a regular hexagon with sides of length 12cm.Round your answer to the nearest whole number. cm2  Match the graph with its equation by writing the color(R,B,G) y=cot(2x) y=cot(1/2x) y=cot(x)  A cube has sides of length 15cm. Find: a) length of EG b) angle AGE Round your answers to the nearest whole number. degrees cm An aeroplane takes off from the ground at the angle of 27o and its average speed in the first 10 seconds is 200km/h.What is the altitude of the plane at the end of this time? Round your answer to the nearest meter. m  1/4csc(3x)+1 1/4sec(3x)+1 Graph below represents the equation: 1/4csc(1/3x)+1 1/4sec(1/3x)+1  Evaluate: = If csc y = cos y = 1 - b2 1 when 0 < y < π 2 then  x = (smaller solution) o y = ( smaller solution) x = tanx = (bigger solution) o y = (bigger solution) o o       , , = = |
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