AIC JS 2 MATHS (3rd Assessment 2nd Term)
 1. Solve x - 2 < 3A) x<-1B) x<1C) x<-5D) x<52. Solve a + 5 > 7A) a < 12B) a > 2C) a > 2D) a > -23. Solve -10 < 5xA) x > -2B) x >= -2C) x < -2D) x > 1/24. Describe the position of point B.A) 2.0B) 0.1C) 0.02D) 0.25. Describe the position of point C.A) 1.15B) 1.4C) 1.5D) 0.56. In the figure above, name the points that have the coordinates (9;5)A) IB) FC) KD) C7. In the figure above, name the points that have the coordinates (-13;15)A) BB) CC) ND) L8. In the figure above, name the points that have the coordinates (14;14)A) EB) BC) DD) A9. Solve -2x < 8A) x < 6B) x > -4C) x > 6D) x < 410. Solve -m >= 7A) m >= -7B) m <= 7C) m <= -7D) m <= 011. If 9 is added to a number x, the result is greater than 17. Find the range of values of x.A) x > 0B) x < 8C) x > 8D) x > 912. Calculate the value of c.A) 8B) 7C) 6D) 513. Calculate the value of PSA) 5B) 7C) 6D) 814. Calculate the value of ADA) 36B) 49C) 64D) 2515. Five times a whole number, x, is subtracted from 62. The result is less than 40. Find the three lowest values of x.A) 5, 6, 7B) 7, 8, 9C) 2, 3, 4D) 0, 1, 216. A book contains 192 pages. A boy reads x complete pages everyday. If he has not finished the book after 10 days, find the highest possible value of x.A) 10B) 19C) 6D) 1217. Use the substitution method to solve a - 2b = 9, 2a + 3b = 4A) a = 3, b= -2B) a = 5, b= -2C) a = 5, b= -1D) a = 5, b= -418. Use the substitution method to solve 3x + 2y = 10, 4x - y = 6A) x = 2, y =3B) x = 2, y =2C) x = 2, y =4D) x = 3, y =419. Use the elimination method to solve 5x + 3y = 1, 2x + 3y= -5A) x =2, y=-3B) x =2, y=2C) x =3, y=1D) x =2, y=-220. Use the elimination method to solve 4x + 3y = 9, 2x + 5y= 15A) x = 3, y =1B) x = 0, y =1C) x = 0, y =3D) x = 0, y = -3
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