(EXAM) JS 3 Math (1st Term)
  • 1. Calculate 11101 - 1011 leaving your answer in base two.
A) 11110
B) 10110
C) 10010
D) 10100
  • 2. Calculate 11110 - 111 leaving your answer in base two.
A) 11001
B) 10111
C) 10001
D) 11011
  • 3. Calculate 1101101 + 11011 leaving your answer in base two.
A) 10001101
B) 11101011
C) 10011101
D) 10001000
  • 4. Calculate 10100 - 1110 leaving your answer in base two.
A) 101
B) 011
C) 110
D) 111
  • 5. Calculate 1100 × 11 leaving your answer in base two.
A) 100100
B) 110011
C) 110100
D) 101101
  • 6. Calculate 111 × (1111 - 1010) leaving your answer in base two.
A) 110011
B) 110111
C) 1010111
D) 100011
  • 7. Find the difference between 63 and the product of 10 and 5
A) 13
B) 21
C) 31
D) 12
  • 8. Find the product of 5 and the difference between 15 and 7
A) 40
B) 4
C) 31
D) 17
  • 9. Find the sum of 16 and the product of 2 and 7
A) 32
B) 19
C) 30
D) 20
  • 10. Find the sum of 0.14 and the product of 0.9 and 0.4
A) 0.42
B) 0.05
C) 0.042
D) 0.5
  • 11. Find the H.C F of 6d2e and 3de2
A) 3
B) 3d
C) 3de
D) 3e
  • 12. Find the H.C F of 8pq and 24p2
A) 8p
B) 6p
C) 3p
D) 2p
  • 13. Find the H.C F of 10ax2 and 14a2x
A) 2ax
B) 2a
C) 4ax
D) ax
  • 14. Find the H.C F of 9xy and 24pq
A) 3pq
B) 6
C) 6pq
D) 3
  • 15. Factorise 3m + m(u -v)
A) m(3+u-v)
B) m(3+v-u)
C) m(3+u+v)
D) m(u+3+v)
  • 16. Factorise 2a - a(3x+y)
A) a(2-3x-y)
B) a(2-3x+y)
C) a(3-2x-y)
D) a(2-3y-x)
  • 17. Factorise x(3-a) + bx
A) x(3-a-b)
B) x(3-a+b)
C) x(3-2b)
D) x(3-a)
  • 18. Factorise (4m-3n)p - 5p
A) p(4m-3n)
B) p(4m-3n+5)
C) p(4m-3n-5)
D) p(4n-3m-5)
  • 19. Factorise a(m+1) + b(m+1)
A) (a+m) (b-m)
B) (m+1) (a-b)
C) (m+1) (a+b)
D) (a-m) (b+m)
  • 20. Factorise a(n+2) - b(n+2)
A) (n+2) (a-b)
B) (n-2) (a+b)
C) (n+2) (a+b)
D) (n-2) (a-b)
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