A) Carbon dioxide B) Methanol C) Water D) Acetone
A) Liquid B) Solid C) Gas D) Supercritical
A) Differences in conductivity B) Differences in molecular weight C) Differences in boiling point D) Differences in solubility in the mobile phase
A) Avoid solvent contamination B) Maintain supercritical conditions C) Enhance detector sensitivity D) Increase column temperature
A) Lower equipment cost B) Limited application range C) Higher resolution D) Faster separation
A) Improves stationary phase selectivity B) Enhances analyte solubility C) Stabilizes column efficiency D) Reduces detector interference
A) Transition zone B) Supercritical zone C) Critical point D) Near-critical region
A) Gas B) Aqueous C) Solid D) Liquid
A) Through exposure to light. B) By altering its chemical composition. C) By changing the pressure and temperature, allowing fine-tuning between liquid-like and gas-like states. D) By adding impurities.
A) At low pressures regardless of temperature. B) When one component is much more volatile than the other, at high pressure and temperatures above the component critical points. C) In all binary mixtures without exception. D) Only when both components have identical critical points.
A) It cannot be estimated; it must always be measured experimentally. B) By summing the critical points of each component. C) Using only the critical temperature of one component. D) As the arithmetic mean of the critical temperatures and pressures of the two components.
A) By averaging the boiling points of the components. B) Equations of state, such as the Peng–Robinson or group-contribution methods. C) Through direct measurement at all possible pressures and temperatures. D) Using only empirical observations without calculations.
A) The density-pressure line B) The boiling curve C) The melting curve D) The critical point
A) 500 K B) 273 K C) 735 K D) 300 K
A) It uses less energy to heat the water. B) It eliminates bubbles on electrodes, reducing ohmic losses. C) It decreases the need for catalysts. D) It increases the volume of hydrogen produced.
A) A continuous reaction system must be devised due to very short reaction times. B) Supercritical conditions can only be achieved at low pressures. C) Large amounts of water are needed to maintain the reaction. D) The process requires long reaction times to be effective.
A) 1.0 megapascal B) 12.0 megapascals C) 9.3 megapascals D) 5.0 megapascals
A) Michael Faraday B) Baron Charles Cagniard de la Tour C) James Prescott Joule D) Benjamin Thompson
A) O2, N2, Ar B) H2, CH4, CO2, CO C) Neon, Krypton, Xenon D) NH3, SO2, NOx
A) Lignin forms a protective layer around polysaccharides. B) Lignin remains unchanged due to short reaction times. C) Lignin is completely converted into simple sugars. D) Aliphatic inter-ring linkages are cleaved into low molecular weight mixed phenols.
A) Increased viscosity B) Reduced density C) Antimicrobial properties D) Enhanced conductivity
A) The Allam cycle B) Rankine cycle C) Otto cycle D) Brayton cycle
A) Cosmetics B) Food science C) Pharmaceuticals D) Microelectronics
A) The density remains constant B) The density decreases significantly C) The density fluctuates unpredictably D) The density becomes higher
A) 100–10000 nm B) 50–500 nm C) 5–2000 nm D) 10–5000 µm
A) 3.4 MPa (34 bar) B) 7.38 MPa (73.8 bar) C) 40 bar D) 570 MPa
A) North Sea gas field B) Alaska gas field C) Sleipner gas field D) Texas gas field
A) Japan B) India C) China D) South Korea
A) 14,000 MPa B) 7.38 MPa (73.8 bar) C) 3.4 MPa (34 bar) D) 570 MPa
A) Lower operational costs. B) Reduced radiation exposure. C) Similar thermal efficiency gains. D) Increased fuel availability.
A) Oxidation B) Hydrogenation C) Transesterification D) Fermentation
A) It enhances the mechanical strength of the aerogel. B) It reduces the cost of materials used. C) It speeds up the drying process significantly. D) It removes solvent without causing distortion due to surface tension.
A) Hydrogen production facilities. B) CO2-based dry cleaning equipment. C) Supercritical fluid extraction equipment. D) Biomass gasification reactors.
A) They increase reaction time. B) They are cheaper than conventional solvents. C) Rapid diffusion accelerates diffusion-controlled reactions. D) They eliminate the need for catalysts. |