A) Water B) Acetone C) Carbon dioxide D) Methanol
A) Solid B) Gas C) Liquid D) Supercritical
A) Differences in molecular weight B) Differences in boiling point C) Differences in solubility in the mobile phase D) Differences in conductivity
A) Enhance detector sensitivity B) Maintain supercritical conditions C) Increase column temperature D) Avoid solvent contamination
A) Limited application range B) Lower equipment cost C) Higher resolution D) Faster separation
A) Enhances analyte solubility B) Reduces detector interference C) Stabilizes column efficiency D) Improves stationary phase selectivity
A) Near-critical region B) Critical point C) Transition zone D) Supercritical zone
A) Aqueous B) Gas C) Solid D) Liquid
A) Through exposure to light. B) By changing the pressure and temperature, allowing fine-tuning between liquid-like and gas-like states. C) By altering its chemical composition. D) By adding impurities.
A) In all binary mixtures without exception. B) At low pressures regardless of temperature. C) Only when both components have identical critical points. D) When one component is much more volatile than the other, at high pressure and temperatures above the component critical points.
A) It cannot be estimated; it must always be measured experimentally. B) As the arithmetic mean of the critical temperatures and pressures of the two components. C) By summing the critical points of each component. D) Using only the critical temperature of one component.
A) Through direct measurement at all possible pressures and temperatures. B) Equations of state, such as the Peng–Robinson or group-contribution methods. C) By averaging the boiling points of the components. D) Using only empirical observations without calculations.
A) The density-pressure line B) The critical point C) The boiling curve D) The melting curve
A) 735 K B) 300 K C) 500 K D) 273 K
A) It decreases the need for catalysts. B) It uses less energy to heat the water. C) It eliminates bubbles on electrodes, reducing ohmic losses. D) It increases the volume of hydrogen produced.
A) Supercritical conditions can only be achieved at low pressures. B) Large amounts of water are needed to maintain the reaction. C) A continuous reaction system must be devised due to very short reaction times. D) The process requires long reaction times to be effective.
A) 1.0 megapascal B) 9.3 megapascals C) 12.0 megapascals D) 5.0 megapascals
A) Benjamin Thompson B) Baron Charles Cagniard de la Tour C) Michael Faraday D) James Prescott Joule
A) O2, N2, Ar B) Neon, Krypton, Xenon C) NH3, SO2, NOx D) H2, CH4, CO2, CO
A) Lignin is completely converted into simple sugars. B) Lignin remains unchanged due to short reaction times. C) Aliphatic inter-ring linkages are cleaved into low molecular weight mixed phenols. D) Lignin forms a protective layer around polysaccharides.
A) Reduced density B) Increased viscosity C) Enhanced conductivity D) Antimicrobial properties
A) Brayton cycle B) Otto cycle C) The Allam cycle D) Rankine cycle
A) Food science B) Cosmetics C) Pharmaceuticals D) Microelectronics
A) The density fluctuates unpredictably B) The density decreases significantly C) The density becomes higher D) The density remains constant
A) 10–5000 µm B) 50–500 nm C) 5–2000 nm D) 100–10000 nm
A) 3.4 MPa (34 bar) B) 7.38 MPa (73.8 bar) C) 570 MPa D) 40 bar
A) North Sea gas field B) Alaska gas field C) Sleipner gas field D) Texas gas field
A) China B) India C) South Korea D) Japan
A) 7.38 MPa (73.8 bar) B) 14,000 MPa C) 570 MPa D) 3.4 MPa (34 bar)
A) Similar thermal efficiency gains. B) Increased fuel availability. C) Reduced radiation exposure. D) Lower operational costs.
A) Hydrogenation B) Oxidation C) Fermentation D) Transesterification
A) It speeds up the drying process significantly. B) It removes solvent without causing distortion due to surface tension. C) It enhances the mechanical strength of the aerogel. D) It reduces the cost of materials used.
A) CO2-based dry cleaning equipment. B) Hydrogen production facilities. C) Supercritical fluid extraction equipment. D) Biomass gasification reactors.
A) They are cheaper than conventional solvents. B) They increase reaction time. C) They eliminate the need for catalysts. D) Rapid diffusion accelerates diffusion-controlled reactions. |