Lesson: Percent Composition

Percent Composition Percent Composition gives the percentage of a substance Percent Composition gives the percentage of a substance that is made up of a certain element. For example, For example, the compound SO _{2}For example, the compound SO _{2}(sulfur dioxide) For example, the compound SO _{2}(sulfur dioxide) has a molar mass of 64.058 For example, the compound SO _{2}Because it has ONE sulfur (sulfur dioxide) has a molar mass of 64.058 For example, the compound SO _{2}Because it has ONE sulfur (sulfur dioxide) has a molar mass of 64.058 one sulfur For example, the compound SO _{2}Because it has ONE sulfur with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 one sulfur For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 two oxygen For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur each with a mass of 16 for a total of 32 with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 two oxygen For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur each with a mass of 16 for a total of 32 with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 this For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur each with a mass of 16 for a total of 32 with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 this plus For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur each with a mass of 16 for a total of 32 with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 this plus this For example, the compound SO _{2}and it has TWO oxygen Because it has ONE sulfur each with a mass of 16 for a total of 32 with a molar mass of 32.06 (sulfur dioxide) has a molar mass of 64.058 this plus equals this this Find the molar mass of the following elements: Carbon Hydrogen Nitrogen Oxygen 12.01 ? 1.01 ? 14.01 ? 16.00 ? Let's find the molar mass H _{2}O.Let's find the molar mass H _{2}O.First, find the molar mass of H and O Let's find the molar mass H _{2}O.First, find the molar mass of H and O O H 16 ? 1.01 ? Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript First, find the molar mass of H and O O H 16 1.01 Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript First, find the molar mass of H and O O H 16 1.01 x x 1 ? 2 ? Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript First, find the molar mass of H and O O H 16 1.01 x x 1 2 = = Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript finally, add the products First, find the molar mass of H and O O H 16 1.01 x x 1 2 = = 16 2.02 Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript finally, add the products First, find the molar mass of H and O 2.02 + 16 = O H 16 1.01 x x 1 2 = = 16 2.02 Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript finally, add the products First, find the molar mass of H and O 2.02 + 16 = O H 16 1.01 x x 18.02 1 2 = = 16 2.02 Let's find the molar mass H _{2}O.then multiply each molar mass by their subscript finally, add the products First, find the molar mass of H and O 2.02 + 16 = O H 16 1.01 x x 18.02 1 2 = = 16 2.02 molar mass of H _{2}OFind the molar mass of the following compounds: H _{2}O_{2}NF _{3}PCl _{4}Al _{2}O_{3}71.01 ? 172.77 ? 34.04 ? 101.96 ? To find percent composition To find percent composition you find the molar mass first To find percent composition you find the molar mass first SO _{2}To find percent composition S O you find the molar mass first SO _{2}To find percent composition S O you find the molar mass first SO _{2}32.06 ? 16 ? To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x 1 ? 2 ? To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 32.06 32 To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 32.06 32 + To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + To find percent composition S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + molar mass Then divide each element's molar mass by the To find percent composition total molar mass S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + Then divide each element's molar mass by the To find percent composition total molar mass S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 Then divide each element's molar mass by the To find percent composition total molar mass S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 = .4995 ? = .5005 ? Then divide each element's molar mass by the To find percent composition total molar mass S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 = .4995 = .5005 Then divide each element's molar mass by the To find percent composition total molar mass, then multiply them both by 100 S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 = .4995 = .5005 Then divide each element's molar mass by the To find percent composition total molar mass, then multiply them both by 100 S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 = .4995x100= = .5005x100= 49.95% ? 50.05% ? Then divide each element's molar mass by the To find percent composition total molar mass, then multiply them both by 100 S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 So SO _{2} is= .4995x100= = .5005x100= 49.95% 50.05% Then divide each element's molar mass by the To find percent composition total molar mass, then multiply them both by 100 S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 So SO _{2} is50.05% Sulfur = .4995x100= = .5005x100= 49.95% 50.05% Then divide each element's molar mass by the To find percent composition total molar mass, then multiply them both by 100 S O you find the molar mass first SO _{2}32.06 16 x x 1 2 = = 64.06 32.06 32 + ÷ 64.06 ÷ 64.06 So SO _{2} is50.05% Sulfur and 49.95% Oxygen = .4995x100= = .5005x100= 49.95% 50.05% Find the percent composition of H _{2}OFind the percent composition of H _{2}OO H Find the percent composition of H _{2}OO H 16 ? 1.01 ? Find the percent composition of H _{2}OO H 16 1.01 x x 1 ? 2 ? Find the percent composition of H _{2}OO H 16 1.01 x x 1 = 2 = 16 ? 2.02 ? Find the percent composition of H _{2}OO H 16 1.01 x x 1 = 2 = 18.02 16 2.02 + Find the percent composition of H _{2}OO H 16 1.01 x x 1 = 2 = 18.02 16 2.02 + ÷ 18.02 = ÷ 18.02 = .8879 ? .1121 ? Find the percent composition of H _{2}OO H 16 1.01 x x 1 = 2 = 18.02 16 2.02 + ÷ 18.02 = ÷ 18.02 = .8879 x100= .1121 x100= 88.79 ? 11.21 ? Find the percent composition of H _{2}OO H 16 1.01 11.21 88.79 x x 1 = 2 = 18.02 16 2.02 % Oxygen ? % Hydrogen ? + ÷ 18.02 = ÷ 18.02 = .8879 x100= .1121 x100= 88.79 11.21 Find the percent composition of NO _{3}.Find the percent composition of NO _{3}.O N Find the percent composition of NO _{3}.O N 16 ? 14.01 ? Find the percent composition of NO _{3}.O N 16 14.01 x x 1 ? 3 ? Find the percent composition of NO _{3}.O N 16 14.01 x x 1 3 = = 48 ? 14.01 ? Find the percent composition of NO _{3}.O N 16 14.01 x x 1 3 = = 48 14.01 + Find the percent composition of NO _{3}.O N 16 14.01 x x 1 3 = = 48 ÷ 62.01 = 62.01 14.01 ÷ 62.01 = + .7741 ? .2259 ? Find the percent composition of NO _{3}.O N 16 14.01 x x 1 3 = = 48 ÷ 62.01 = 62.01 14.01 ÷ 62.01 = + .7741x100= .2259 x100= 77.41 ? 22.59 ? Find the percent composition of NO _{3}.O N 16 14.01 x x 77.41% 22.59% 1 3 = = 48 ÷ 62.01 = 62.01 14.01 ÷ 62.01 = + Oxygen ? Nitrogen ? .7741x100= .2259 x100= 77.41 22.59 |

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