Changing from Standard Form to Slope-Int Form
The slope-intercept form
The slope-intercept form
y = mx + b
The slope-intercept form
y = mx + b
always has y...
The slope-intercept form
y = mx + b
always has y...
...absolutely...
The slope-intercept form
y = mx + b
always has y...
...absolutely...
...totally...
The slope-intercept form
y = mx + b
always has y...
...absolutely...
...totally...
...all by itself.
The slope-intercept form
y by itself
y = mx + b
always has y...
...absolutely...
...totally...
...all by itself.
The standard form
The standard form
Ax + By = C
The standard form
Ax + By = C
always has...
The standard form
Ax + By = C
always has...
x and y on one side,
x and y on one side
The standard form
Ax + By = C
always has...
x and y on one side,
The standard form
Ax + By = C
and everything else on the other side
always has...
x and y on one side,
The standard form
Ax + By = C
and everything else on the other side
always has...
x and y on one side,
everything else

2x + 3y = 4

Standard
?
Match the equation with its form.
Slope-intercept
?
y = 2x + 5
an equation
To change any equation
x + y = 5
To change any equation
x + y = 5
into slope intercept form
To change any equation
x + y = 5
into slope intercept form
y = mx + b
To change any equation
x + y = 5
into slope intercept form
y = mx + b
you have to get y by itself
This y needs to be alone
To change any equation
x + y = 5
into slope intercept form
y = mx + b
you have to get y by itself
To do this we use Algebra
To do this we use Algebra
x + y = 5
To do this we use Algebra
x + y = 5
we need to get y by itself
so we need to get rid of the x
To do this we use Algebra
x + y = 5
we need to get y by itself
To do this we use Algebra
-x
x + y = 5

-x

subtract x on both sides
To do this we use Algebra
-x
x + y = 5

-x

subtract x on both sides
to get rid of the x
To do this we use Algebra

x - x

cancels

-x
x + y = 5

-x

subtract x on both sides
to get rid of the x
To do this we use Algebra

x - x

cancels

Leaving just y on that side
-x
x + y = 5
y =

-x

subtract x on both sides
to get rid of the x
To do this we use Algebra
are not like terms
since 5 and -x
-x
x + y = 5
y =

-x

subtract x on both sides
to get rid of the x
we can't add them
To do this we use Algebra
are not like terms
since 5 and -x
-x
x + y = 5
y =

-x

subtract x on both sides
to get rid of the x
we can't add them
To do this we use Algebra
are not like terms
since 5 and -x
-x
x + y = 5
y = -x + 5

-x

leaving us with this
subtract x on both sides
to get rid of the x
To do this we use Algebra
The y is by itself now
-x
x + y = 5
y = -x + 5

-x

To do this we use Algebra
so this equation is in slope-intercept form
The y is by itself now
-x
x + y = 5
y = -x + 5

-x

standard equation
We changed this
x + y = 5
y = -x + 5
standard equation
We changed this
x + y = 5
y = -x + 5
slope-intercept equation
into this
Match the equation with its form

6x - 2y = 12

Standard
?
Slope-intercept
?

y = 4x

Match the equation with its form
Slope-intercept
?

y = 3x + 1

-4x - y = 4

Standard
?
Match the equation with its form

x + y = 5

Standard
?
Slope-intercept
?

y = x + 5

Match the equation with its form
Slope-intercept
?

y = -2x - 4

x - 5y = 9

Standard
?
Which equation is equivalent to 4x - 3y = 9?

y = -4x + 9

y = 4/3x - 3

y = -4/3x - 3

y = -3/4x - 3

Which equation is equivalent to x + 3y = -6?

y = -1/3x - 2

y = -3x - 3

y = -3x - 2

y = -x - 6

Which equation is equivalent to 2x - y = 8?

y = -x + 4

y = -2x + 8

y = 2x + 4

y = 2x - 8

Which equation is equivalent to y = 3x - 1?
6x - 2y = 2 

3x + y = 1

-3x - y = 1

6x + 2y = 2

In changing from standard form

to slope-intercept form, what should be your

first step?

Find slope

Divide by the y-coefficient

Add or Subtract the "Ax" term

Divide each side by the "Ax" term

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