A) Acetone B) Water C) Carbon dioxide D) Methanol
A) Gas B) Liquid C) Solid D) Supercritical
A) Differences in conductivity B) Differences in boiling point C) Differences in molecular weight D) Differences in solubility in the mobile phase
A) Avoid solvent contamination B) Enhance detector sensitivity C) Increase column temperature D) Maintain supercritical conditions
A) Limited application range B) Higher resolution C) Lower equipment cost D) Faster separation
A) Reduces detector interference B) Improves stationary phase selectivity C) Enhances analyte solubility D) Stabilizes column efficiency
A) Critical point B) Transition zone C) Near-critical region D) Supercritical zone
A) Aqueous B) Solid C) Liquid D) Gas
A) By changing the pressure and temperature, allowing fine-tuning between liquid-like and gas-like states. B) Through exposure to light. C) By adding impurities. D) By altering its chemical composition.
A) In all binary mixtures without exception. B) Only when both components have identical critical points. C) At low pressures regardless of temperature. D) When one component is much more volatile than the other, at high pressure and temperatures above the component critical points.
A) It cannot be estimated; it must always be measured experimentally. B) By summing the critical points of each component. C) As the arithmetic mean of the critical temperatures and pressures of the two components. D) Using only the critical temperature of one component.
A) Through direct measurement at all possible pressures and temperatures. B) Using only empirical observations without calculations. C) By averaging the boiling points of the components. D) Equations of state, such as the Peng–Robinson or group-contribution methods.
A) The critical point B) The melting curve C) The density-pressure line D) The boiling curve
A) 273 K B) 735 K C) 500 K D) 300 K
A) It uses less energy to heat the water. B) It eliminates bubbles on electrodes, reducing ohmic losses. C) It increases the volume of hydrogen produced. D) It decreases the need for catalysts.
A) A continuous reaction system must be devised due to very short reaction times. B) Large amounts of water are needed to maintain the reaction. C) Supercritical conditions can only be achieved at low pressures. D) The process requires long reaction times to be effective.
A) 1.0 megapascal B) 5.0 megapascals C) 9.3 megapascals D) 12.0 megapascals
A) Baron Charles Cagniard de la Tour B) James Prescott Joule C) Michael Faraday D) Benjamin Thompson
A) H2, CH4, CO2, CO B) Neon, Krypton, Xenon C) O2, N2, Ar D) NH3, SO2, NOx
A) Lignin is completely converted into simple sugars. B) Lignin forms a protective layer around polysaccharides. C) Lignin remains unchanged due to short reaction times. D) Aliphatic inter-ring linkages are cleaved into low molecular weight mixed phenols.
A) Enhanced conductivity B) Reduced density C) Antimicrobial properties D) Increased viscosity
A) Rankine cycle B) Brayton cycle C) Otto cycle D) The Allam cycle
A) Microelectronics B) Cosmetics C) Pharmaceuticals D) Food science
A) The density remains constant B) The density decreases significantly C) The density fluctuates unpredictably D) The density becomes higher
A) 50–500 nm B) 100–10000 nm C) 5–2000 nm D) 10–5000 µm
A) 3.4 MPa (34 bar) B) 40 bar C) 7.38 MPa (73.8 bar) D) 570 MPa
A) Texas gas field B) Sleipner gas field C) North Sea gas field D) Alaska gas field
A) Japan B) India C) China D) South Korea
A) 3.4 MPa (34 bar) B) 570 MPa C) 14,000 MPa D) 7.38 MPa (73.8 bar)
A) Reduced radiation exposure. B) Lower operational costs. C) Similar thermal efficiency gains. D) Increased fuel availability.
A) Fermentation B) Transesterification C) Oxidation D) Hydrogenation
A) It enhances the mechanical strength of the aerogel. B) It removes solvent without causing distortion due to surface tension. C) It speeds up the drying process significantly. D) It reduces the cost of materials used.
A) Biomass gasification reactors. B) Hydrogen production facilities. C) Supercritical fluid extraction equipment. D) CO2-based dry cleaning equipment.
A) They are cheaper than conventional solvents. B) They increase reaction time. C) They eliminate the need for catalysts. D) Rapid diffusion accelerates diffusion-controlled reactions. |