(EXAM) JS 3 Math (1st Term)
  • 1. Calculate 11101 - 1011 leaving your answer in base two.
A) 10010
B) 10100
C) 11110
D) 10110
  • 2. Calculate 11110 - 111 leaving your answer in base two.
A) 11001
B) 10111
C) 11011
D) 10001
  • 3. Calculate 1101101 + 11011 leaving your answer in base two.
A) 10011101
B) 10001101
C) 11101011
D) 10001000
  • 4. Calculate 10100 - 1110 leaving your answer in base two.
A) 101
B) 111
C) 110
D) 011
  • 5. Calculate 1100 × 11 leaving your answer in base two.
A) 110100
B) 100100
C) 110011
D) 101101
  • 6. Calculate 111 × (1111 - 1010) leaving your answer in base two.
A) 1010111
B) 100011
C) 110111
D) 110011
  • 7. Find the difference between 63 and the product of 10 and 5
A) 12
B) 21
C) 13
D) 31
  • 8. Find the product of 5 and the difference between 15 and 7
A) 17
B) 40
C) 31
D) 4
  • 9. Find the sum of 16 and the product of 2 and 7
A) 30
B) 20
C) 32
D) 19
  • 10. Find the sum of 0.14 and the product of 0.9 and 0.4
A) 0.05
B) 0.5
C) 0.42
D) 0.042
  • 11. Find the H.C F of 6d2e and 3de2
A) 3e
B) 3
C) 3d
D) 3de
  • 12. Find the H.C F of 8pq and 24p2
A) 3p
B) 8p
C) 6p
D) 2p
  • 13. Find the H.C F of 10ax2 and 14a2x
A) 2a
B) 2ax
C) 4ax
D) ax
  • 14. Find the H.C F of 9xy and 24pq
A) 3pq
B) 3
C) 6
D) 6pq
  • 15. Factorise 3m + m(u -v)
A) m(3+u+v)
B) m(3+u-v)
C) m(3+v-u)
D) m(u+3+v)
  • 16. Factorise 2a - a(3x+y)
A) a(2-3x+y)
B) a(3-2x-y)
C) a(2-3y-x)
D) a(2-3x-y)
  • 17. Factorise x(3-a) + bx
A) x(3-a-b)
B) x(3-2b)
C) x(3-a)
D) x(3-a+b)
  • 18. Factorise (4m-3n)p - 5p
A) p(4m-3n-5)
B) p(4m-3n+5)
C) p(4m-3n)
D) p(4n-3m-5)
  • 19. Factorise a(m+1) + b(m+1)
A) (m+1) (a-b)
B) (m+1) (a+b)
C) (a+m) (b-m)
D) (a-m) (b+m)
  • 20. Factorise a(n+2) - b(n+2)
A) (n-2) (a+b)
B) (n+2) (a+b)
C) (n-2) (a-b)
D) (n+2) (a-b)
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