(EXAM) JS 3 Math (1st Term)
- 1. Calculate 11101 - 1011 leaving your answer in base two.
A) 10010
B) 10110
C) 10100
D) 11110
- 2. Calculate 11110 - 111 leaving your answer in base two.
A) 10111
B) 10001
C) 11011
D) 11001
- 3. Calculate 1101101 + 11011 leaving your answer in base two.
A) 10001101
B) 10011101
C) 10001000
D) 11101011
- 4. Calculate 10100 - 1110 leaving your answer in base two.
A) 101
B) 110
C) 011
D) 111
- 5. Calculate 1100 × 11 leaving your answer in base two.
A) 110100
B) 110011
C) 100100
D) 101101
- 6. Calculate 111 × (1111 - 1010) leaving your answer in base two.
A) 110111
B) 1010111
C) 100011
D) 110011
- 7. Find the difference between 63 and the product of 10 and 5
A) 31
B) 13
C) 21
D) 12
- 8. Find the product of 5 and the difference between 15 and 7
A) 31
B) 17
C) 40
D) 4
- 9. Find the sum of 16 and the product of 2 and 7
A) 30
B) 32
C) 19
D) 20
- 10. Find the sum of 0.14 and the product of 0.9 and 0.4
A) 0.5
B) 0.42
C) 0.042
D) 0.05
- 11. Find the H.C F of 6d2e and 3de2
A) 3d
B) 3e
C) 3de
D) 3
- 12. Find the H.C F of 8pq and 24p2
A) 8p
B) 6p
C) 2p
D) 3p
- 13. Find the H.C F of 10ax2 and 14a2x
A) 4ax
B) ax
C) 2a
D) 2ax
- 14. Find the H.C F of 9xy and 24pq
A) 6
B) 3
C) 6pq
D) 3pq
- 15. Factorise 3m + m(u -v)
A) m(u+3+v)
B) m(3+u+v)
C) m(3+u-v)
D) m(3+v-u)
- 16. Factorise 2a - a(3x+y)
A) a(2-3x+y)
B) a(2-3x-y)
C) a(3-2x-y)
D) a(2-3y-x)
- 17. Factorise x(3-a) + bx
A) x(3-a)
B) x(3-a+b)
C) x(3-2b)
D) x(3-a-b)
- 18. Factorise (4m-3n)p - 5p
A) p(4m-3n)
B) p(4m-3n-5)
C) p(4n-3m-5)
D) p(4m-3n+5)
- 19. Factorise a(m+1) + b(m+1)
A) (a+m) (b-m)
B) (m+1) (a+b)
C) (m+1) (a-b)
D) (a-m) (b+m)
- 20. Factorise a(n+2) - b(n+2)
A) (n-2) (a-b)
B) (n+2) (a-b)
C) (n-2) (a+b)
D) (n+2) (a+b)
|
Students who took this test also took :